Parsing Roman Numerals into Base-10 Integers Using Python

Problem Definition

The objective is to translate a given valid Roman numeral string into its corresponding base-10 integer. The input will always represent a number within the range of 1 to 3999.

Roman Numeral Notation Rules

Roman numerals are constructed using seven primary symbols: I, V, X, L, C, D, and M, representing values 1, 5, 10, 50, 100, 500, and 1000 respectively. The conversion relies primarily on two positional principles:

  • Addditive Principle: When a smaller or equal symbol appears after a larger one, their values are summed (e.g., VI equals 6).
  • Subtractive Principal: When a smaller symbol precedes a larger one, the smaller value is deducted from the larger (e.g., IV equals 4). Subtraction follows strict ordering rules and never skips adjacent numerical positions.

Algorithmic Strategy

A forward-pass approach requires inspecting the next character to decide whether to add or subtract the current value, which complicates boundary handling at the end of the string. A more efficient and cleaner method processes the sequence from right to left. By tracking the value of the previously encountered symbol, we can apply the subtraction rule deterministically: if the current symbol's value is strictly less than the previous symbol's value, it belongs to a subtractive pair and must be subtracted. Otherwise, it is added. This eliminates index arithmetic and simplifies state management.

Implementation

class Solution:
    def romanToInt(self, s: str) -> int:
        symbol_map = {
            'I': 1, 'V': 5, 'X': 10, 'L': 50,
            'C': 100, 'D': 500, 'M': 1000
        }
        
        accumulated_value = 0
        previous_value = 0
        
        for char in reversed(s):
            current_value = symbol_map[char]
            
            if current_value < previous_value:
                accumulated_value -= current_value
            else:
                accumulated_value += current_value
                
            previous_value = current_value
            
        return accumulated_value

Performance Characteristics

The routine iterates through the input string exactly once, executing constant-time dictionary lookups and arithmetic comparisons per character. This yields a linear time complexity of O(n), where n denotes the string length. Memory consumption remains constant at O(1), as the lookup table contains a fixed set of entries and only two integer variibles scale with execution state.

Tags: python algorithmic-patterns string-parsing leetcode-13 roman-numerals

Posted on Wed, 13 May 2026 17:20:10 +0000 by lordrain11