Freaks City

This week's practice focuses on mastering binary search algorithms through LeetCode problems. The first problem is Binary Search. Below is the implementation: int search(int* nums, int numsSize, int target) { int left = 0; int right = numsSize - 1; while (left <= right) { int mid = left + (right - left) / 2; if ( ...

Maximizing Minimum Distance Between ElementsGiven an array of unique positions and a number of items to place, the goal is to position the items such that the minimum absolute difference between any two items' positions is maximized.Example 1:Input: positions = [1,2,3,4,7], items = 3Output: 3Explanation: Placing items at positions 1, 4, and 7 y ...

A. Programming Contest This problem is a straightforward implementation task. The idea is to count the number of valid years betweeen two given years, excluding specific invalid years provided in the input. void solve() { int n, m; std::cin >> n; std::vector<int> invalidYearFlag(10000, 0); // Assuming a safe upper bound ...

When numerous queries each admit a binary search solution, but performing binary search individually for every query is too slow, we can process all queries together using a technique known as simultaneous binary search (also called "parallel binary search" or "global binary search"). This approach requires: Queries to be h ...

Binary search operates with O(log n) time complexity on a sorted array of n elements. The algorithm repeatedly divides the search interval in half, achieving logarithmic performance. Algorithm Fundamentals Binary search, also known as half-interval search, is an efficient algorithm for locating a target value within a sorted sequence. It compar ...

Problem A: Road Construction Description There are n initially isolated cities. In each round, every city connects to its nearest neighbor. If a cycle formss during a round, the shortest edge in that cycle is removed. Once cities are connected, they form a "union" and act as a single entity in subsequent rounds. The process continues ...

Problem StatementGiven an array of integers sorted in non-decreasing order, identify the starting and ending index of a specified target value. If the target is absent from the array, return [-1, -1]. The solution must operate with a logarithmic time complexity of O(log n).Expected OutcomesFor data = [5, 7, 7, 8, 8, 10], target = 8, the output ...

Finding Saddle Points in a 2D Array A saddle point in an m×n matrix is an element that is both the maximum in its row and the minimum in its column. #include <stdio.h> void locateSaddlePoint(int matrix[100][100], int rows, int cols) { for (int row = 0; row < rows; row++) { int rowMax = matrix[row][0]; int maxCol = ...

Interactive programming challenges require a different approach than standard I/O problems. Instead of reading from standard input and writing to standard output, the solution communicates directly with a judging system through predefined function calls. This architecture is commonly referred to as a grader-based interaction model. In a typical ...

This problem requires finding the minimum number of adjacent swaps to sort an array containing a permutation of numbers from 1 to n. The cost of each adjacent swap is 1. The key insight is that each adjacent swap changes the number of inversions in the array by exactly one. To sort the array in ascending order, we aim to eliminate all inversion ...