Multi-Round Elimination Voting System Simulation
Problem Overview
In a competitive selection process, $n$ judges vote for $m$ available brands using a multi-round elimination system. The goal is to determine if a single brand can emerge as the winner or if the selection fails due to a tie in the final round.
Elimination Rules
The process follows these logic steps until a result is determined: ...
Posted on Mon, 22 Jun 2026 16:34:51 +0000 by oldtimer
Ad-hoc Training
Difficulty range [1, 10], where ≤ 5 is easy, 6 requires thinking for ≤ 30min, 7 is barely solvable (1h). 8 means it's unsolvable but seems not difficult. 9 is currently unsolvable but can be naturally derived from the solution. 10 is extremely difficult to understand even the solution.
Thinking time should be around [40, 80] min, not ≤ 30 min.
...
Posted on Sat, 20 Jun 2026 17:01:21 +0000 by philvia
Solutions to AGC016 Programming Contest Problems
A - Shrinking
Given a string s, determine the minimum number of operasions required to make all characters identical. Each operation reduces the string length by one by selecting characters from adjacent positions.
#include <bits/stdc++.h>
using namespace std;
int main() {
string input;
cin >> input;
int length = input. ...
Posted on Fri, 19 Jun 2026 17:54:39 +0000 by decodv
Algorithmic Review and Competition Strategies for NOIP
Contest preparation requires a structured approach to covering fundamental algorithms and optimizing problem-solving strategies. The following outlines core technical topics and execution practices essential for competitive programming.
Core Algorithms and Data Structures
Simulation and Mathematics
High-precision arithmetic is critical for p ...
Posted on Mon, 15 Jun 2026 17:54:23 +0000 by press711
Core Algorithmic Techniques in Java for Competitive Programming
Sorting, searching, dynamic programing, and graph algorithms form the backbone of competitive programming. This article presents a curated list of such patterns, each accompanied by a concise Java implementation. The examples draw inspiration from the ACwing problem set, covering topics from basic sorting to advanced combinatorial mathematics.
...
Posted on Mon, 15 Jun 2026 17:07:00 +0000 by zhaohongli
Solving Problems ABC 269 (A-G)
A: Basic Arithmetic and Output
Given integers a, b, c, d, compute (a + b) * (c - d) and output the result followed by the string "Takahashi".
int a = input(), b = input(), c = input(), d = input();
cout << (a + b) * (c - d) << endl;
cout << "Takahashi" << endl;
Time complexity: O(1)
B: Finding Corne ...
Posted on Wed, 10 Jun 2026 16:36:46 +0000 by Elephant
Problem Solving Approaches for AtCoder Beginner Contest 045
Problem A: Trapezoid Area
Given the upper base $a$, lower base $b$, and height $h$ of a trapezoid, the area is calculated using the formula:
$$\text{Area} = \frac{(a + b) \times h}{2}$$
Problem B: Card Game for Three
Three players, A, B, and C, each start with a string of cards. Starting with player A, they draw cards in a sequence. If a player ...
Posted on Tue, 09 Jun 2026 17:50:46 +0000 by Ben5on
Competitive Programming Code Templates and Common Algorithms
Header File Templates
C++ Template
#include <bits/stdc++.h>
#define fi first
#define endl '\n'
#define se second
#define lowbit(x) ((x)&(-(x)))
#define all(x) begin(x), end(x)
#define lp(i, j, k) for(int i = int(j); i <= int(k); i++)
#define rlp(i, j, k) for(int i = int(j); i >= int(k); i++)
#define IO std::ios::sync_with_std ...
Posted on Mon, 08 Jun 2026 17:51:31 +0000 by atstein
Algorithmic Solutions for String Processing, Greedy Maximization, and Graph Dependencies
Prefix Matching and Keyboard Layout Reconstruction
This problem involves identifying possible next characters based on a given prefix and mapping them to a specific $4 \times 8$ grid layout. The core task is to filter a list of strings that start with a specific sequence and mark the character that immediately follows that sequence.
#include &l ...
Posted on Sun, 07 Jun 2026 16:46:38 +0000 by rednax
Contest Problem Solutions: Factorization, Rays, String Construction, and Tree Partitioning
Factorization into Factorial Divisors
Given integers (n) and (m) where (1 \le m \le n!) and (n \le 20), decompose (m) into a sum of at most (n) divisors of (n!). A solution is guaranteed to exist.
Define a sequence (d_i = \frac{n!}{i!}) for (i) from 1 to (n). By iterating downwards from (i=n) to (1) and greedily subtracting the largest possible ...
Posted on Mon, 01 Jun 2026 17:41:27 +0000 by taldos