Min-Cost Circular Merging and Multiset Counting via Knapsack
Circular Array Merging with Max-Cost
We are given a circular array of positive integers. In one step we can pick any two adjacent elements, remove them, and pay a cost equal to the larger of the two values. The goal is to reduce the array to a single element while minimiizng the total cost.
Key observation
Because every merge can only increase- ...
Posted on Tue, 03 Nov 2026 16:13:31 +0000 by wrwilson
Validating Non-Decreasing Arrays with Single Increment Constraints
Greedy Validation of Monotonic SequencesDetermining whether an array can be transformed into a non-decreasing sequence under specific modification rules requires a greedy traversal approach. The core condition involves checking adjacent elements and applying a limited increment operation when a descending pair is encountered.Algorithmic Strateg ...
Posted on Sat, 31 Oct 2026 16:00:22 +0000 by Cannibal_Monkey
Educational Codeforces Round 162 (Rated for Div. 2) - Virtual Participation Notes
Preface
This virtual contest didn't go as smoothly as expected. I spent longer than anticipated on problem B. For problem D, I identified the solution approach quickly but failed to account for several edge cases, resulting in three wrong submissions. Moving forward, I need to pay closer attention to edge cases during competition and work throu ...
Posted on Sat, 24 Oct 2026 16:19:20 +0000 by trystan
Greedy Algorithms for Interval Problems: Non-overlapping Intervals, Partition Labels, and Merging Ranges
Remove Minimum Intervals to Eliminate Overlaps
Given a list of intervals, determine the minimum number of intervals to remove so that the remaining ones do not overlap. Adjacent intervals like [1,2] and [2,3] are not considered overlapping.
A greedy approach works by sorting intervals by their end points. After sorting, iterate through the list ...
Posted on Wed, 21 Oct 2026 16:22:22 +0000 by Dark[NSF]
Algorithm Enhancement — Summary of LeetCode Weekly Contest 386
Problems
Data Partitioning
Given an integer array nums of even length, split it into two arrays nums1 and nums2, such that:
nums1.length == nums2.length == nums.length / 2
Both nums1 and nums2 contain unique elements.
Return true if the array can be partitioned in this way, otherwise return false.
Approach
Use a hash map to count occurrences ...
Posted on Wed, 21 Oct 2026 16:10:34 +0000 by Viper_4
Determining Representability of an Integer as a Sum of 2020 and 2021 Multiples
Given a positive integer $ n $, determine whether it can be expressed as a non-negative integer combination of 2020 and 2021 — that is, whether there exist integers $ a \geq 0 $ and $ b \geq 0 $ such that:
$$
n = 2020a + 2021b
$$
Rewriting the equation reveals a useful structure:
$$
n = 2020(a + b) + b = 2020k + b,
$$
where $ k = a + b $. Since ...
Posted on Wed, 14 Oct 2026 16:39:25 +0000 by Spiz
Maximum Area of a Piece of Cake After Horizontal and Vertical Cuts
Given a rectangular cake of height h and width w, and two integer arrays horizontalCuts and verticalCuts where horizontalCuts[i] is the distance from the top of the cake to the i-th horizontal cut and verticalCuts[j] is the distance from the left side of the cake to the j-th veritcal cut, return the maximum area of a peice of cake after you cut ...
Posted on Sun, 11 Oct 2026 16:56:14 +0000 by froggie81
Solutions to Educational Codeforces Round 162
This problem requires counting the number of zeros between the first and last occurrence of 1 in an array.
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
void solve() {
int n;
cin >> n;
vector<int> arr(n);
int firstOne = -1, lastOne = -1;
for (int i = 0; i < n; i++) {
...
Posted on Wed, 07 Oct 2026 16:56:53 +0000 by basil
CodeForces 1406 - Codeforces Round #670 (Div. 2) Editorial
Contest Overview
This round was relatively straightforward, so this editorial will focus on both the technical problem solutions and the interesting sequence of events during the contest.
Problem A - Subset Mex
Problem Statement: Given a set a with |a| = n, partition it into two sets A and B to maximize mex(A) + mex(B). Multiple test cases.
Con ...
Posted on Tue, 06 Oct 2026 16:45:21 +0000 by Brendan Nolan
Programming Contest Solutions and Analysis
Contest Overview
Total Score: 290
Ranking: 3
Problems Solved: 2
Problem Solutions
Problem 1: Interview Screening
Score: 100
**Analysis:**This is a relatively straightforward problem that resembles bucket sorting. The key is to properly handle the conditional checks without mixing them up.
Implementation:
// Store possible outcomes
string result ...
Posted on Sun, 04 Oct 2026 16:07:53 +0000 by dswain