Freaks City

Problem Description KiKi has a matrix and wants to determine the matrix after performing k row or column swap operations. Please write a program to solve this. Input Description: The first line contains two integers n and m (separated by a space), representing a matrix with n rows and m columns (1 ≤ n ≤ 10, 1 ≤ m ≤ 10). From line 2 to line n+1 ...

Given an N x N matrix of integers, compute the maximum sum of any non-empty submatrix. This problem can be efficiently solved by extending the one-dimensional maximum subarray problem (Kadane's algorithm) to two dimensions using prefix sums. First, precompute a prefix sum array prefixSum where prefixSum[i][j] stores the cumulative sum of elemen ...

Given a tournament with n teams numbered from 0 to n - 1, determine the champion based on match results represented in an n x n boolean matrix. Each element grid[i][j] indicates whether team i defeats team j. If grid[i][j] is 1, then team i is stronger than team j. Otherwise, team j is stronger than team i. A champion is a team that no other te ...

Array Increment Operation Given a non-empty array representing a non-negative integer, increment the number by one. Each element stores a single digit, with the most significant digit at the head of the list. class Solution: def plusOne(self, digits: List[int]) -> List[int]: length = len(digits) # Traverse from rightmost ...

Importing and Using NumPy NumPy provides essential matrix operations. To use its functions, import the library as follows: import numpy as np # Standard import with np prefix from numpy import * # Alternative import for direct access Creating Matrices Create matrices from one or two-dimensional data: >>> import numpy as np >>&g ...

Problem Description: There are n teams numbered from 0 to n - 1 in a tournament. You are given a 0-indexed 2D boolean matrix grid of size n * n. For all i, j such that 0 <= i, j <= n - 1 and i != j, if grid[i][j] == 1, then team i is stronger than team j; otherwise, team j is stronger than team i. If there is no team that is stronger than ...

Fabric.js provides viewport manipulation capabilities through the viewportTransform property, allowing developers to control how the entire canvas appears to users. The viewportTransform property leverages native canvas transformation functionality, essentially wrapping the canvas 2D API's transform() method. According to the official documenta ...

In a binary matrix of size m x n, a subset of rows is considered "good" if, for every column, the sum of the elements in that column does not exceed half the size of the subset. Formally, if the subset conntains k rows, the sum of each column must be less than or equal to floor(k / 2). The goal is to return the indices of such a subse ...

Problem Statement Given an n×m integer matrix and q queries, each query specifies the coordinates of the top-left and bottom-right corners of a submatrix. For each query, compute the sum of all elements within the specified submatrix. Solution Approach The problem can be efficiently solved using 2D prefix sums. By precomputing the cumulative su ...

Problem Analysis The spiral matrix traversal problem requires printing matrix elements in a clockwise spiral pattern, starting from the top-left corner and moving inward layer by layer. The traversal follows a consistent pattern: move right along the top edge, then down the right edge, then left along the bottom edge, and finally up the left ed ...