Block Partitioning for Summing Numbers with Odd Bit Count
Problem Transformation
The core task reduces to computing the sum of all numbers in ([0, N]) whose popcount is odd:
$$\sum_{i=0}^{N} [popcount(i) \bmod 2 = 1]$$
where the Iverson bracket ([p]) equals 1 when (p) is true and 0 otherwise.
Block Partitioning Strategy
When analyzing addition contributions of all numbers in ([0, N]) under binary repr ...
Posted on Sun, 11 Oct 2026 16:57:57 +0000 by Pig